Sql sum double counting. Follow edited Apr 28, 2021 at 23:27.
Sql sum double counting The fiddle (adjusted to also show the original result) Try changing UNION to UNION ALL, like this. It runs a logical test; in the case when the expression is true, then it will assign a specific value to it. AS FULL_NAME, COUNT(DISTINCT Discover real-world use cases of the SUM() function with OVER(PARTITION BY) clause. In this I have an excel spreadsheet which pulls records from SQL. s_id) . Avoid double counting 1. SQL Server : query with incorrect SUM result SUM result is double what it should be. Basically, you should aggregate A's and B's results seperately and verify the counts after that. The first query gets the sum of all attempts for each quiz: SELECT quiz_id, SUM(attempts) as sum FROM quizzes GROUP BY quiz_id The second query gets counts the number of times a quiz has been passed: SELECT quiz_id, COUNT(*) as count FROM quizzes WHERE has_passed =1 GROUP BY quiz_id join double-counting Tom, I am joining two tables. I need to group by Tsp. Ask Question Asked 10 years, 10 months ago. Modified 5 years, ) L on I. mRate) as TotalExpense FROM [Owners] inner join Portfolio on Portfolio. As soon as you JOIN you have expanded the results to be at the granularity of the opportunity. date) from data_b as c where a. PersonID; SQL Server does integer division. Commented Oct 1, 2018 at 22 The default way to avoid double counting is to use SUM(DISTINCT expr). Yeah, I need some sort of set analysis. Note: If the field you ORDER BY isn't unique (for instance, if you're ordering over the top N rows by some integer metric, and finding a cumulative sum of that metric), this will produce subtly incorrect results, with the same cumulative sum shown for all rows where that value is equal. If fee. That seems cleaner and clearer to me. How to sum just the decimal values from a Your JOINs and / or GROUP BY clause are incorrect, causing the increased number of rows. Thus, summing will I am trying to create a market basket query. invoices INNER JOIN adass. You did say: get the name of each user. Modified 6 years, 8 months ago. I have an issue with this mysql query. COUNT(DISTINCT expression) - evaluates expression for each row in a One solution would be to change the sum to:, <earlier columns> , ( select SUM(payments. We use SQL window functions to perform operations on groups of data. using sum and count inside case sql statement. Viewed 50 times -2 So I am working with data that has a premise ID and a subscriber ID. ProjectId = p. Modified 8 years, 7 months ago. Both queries are almost same with same column used in GROUP BY clause, so you can combine them in single query having both aggregate functions COUNT() and SUM(). Here's what mySQL SUM and COUNT issue, some values on join get doubled. it has to show 4 based on the row number in inv_lst table but here it is showing 8. When I use sum or count in my query, I get double the correct result. TrackTime)) where speed<3 as LostTime ,SUM(DATEDIFF(minute, a. My query returns all rows so 1/2 way there. SQL Fiddle DEMO SELECT Name, COUNT(1) as Cnt FROM Table1 GROUP BY Name UNION ALL SELECT 'SUM' Name, COUNT(1) FROM Table1 The reason for this is that you have joined the table the first derived table from the second table without grouping it. CREATE TaBLE activities (status_id Integer, `date` Date ); Oracle double count case. trackold, a. Current Query: select pa. sum result is being multiplied by number of rows. TotalCost, d. Example #2: GROUP BY Multiple Columns. I am writing a macro which pulls data from Oracle and displays in Excel. Below is the table structures. Yields the same, incorrect result as your original, but simpler / faster / easier SUM () is done after you're done your JOIN, and your JOIN appears to be matching one record from one talbe to two records from the other table. Sales END) AS Total_Sales FROM Sales s JOIN Sales_period sp ON s. Oracle SQL Count or Sum in case query? Ask Question Asked 6 years, 3 months ago. Let me show you the logic and the CASE WHEN syntax in an example. As i don't use a GROUP BY in my correct answer, SUM is the only solution. ties) AS ties. Current work around is 3 separate sum queries one for each table, but that is going to get inefficient and added steps. losses) AS losses. basically I need to join one table (CostiFissi, a table with costs) with a table with payments (Pagamenti), grouping them by cost id (CostiFissi_IdCostoFisso) and calculating the average between monthly sums of payments amount (not just AVG(Totale) ). I think that would be the best route available to you. – Why are you summing already counted participants? Just use count, multiply by fee and that's all. Great. LOGMINS column - therefore it follows that the COALESCE (SUM(CASE WHEN C. Double_Period = 'T' THEN 2 * s. participant_id) * c. Count in SQL Server table. tbl_receipt id receipt_no member_id receipt_amount 1 21001 21 20500 2 21002 Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company Visit the blog This example works the same way as our initial query. Commented Jun 15, 2016 at 8:10. Then only add in the key field of each Table as you go, and uncomment a single JOIN one by one until you start Try this query. name)) as sumcount FROM table 1 as d group by d. It's just the first Sum seems to double/triple count when left joining two tables. I'm struggling with a query where I need to SUM DISTINCT Rows. it should not double count AE - GB and DE - US. Modified 6 years, 10 months ago. Example 1: The CASE WHEN Expression. payments ON invoices. Improve this question. Getting a SUM of the values in INNER JOIN adds up duplicate values. If I do a simple join, it is summing up the row value from EVEN I have a scenario where I believe multiple joins are causing aggregate functions (a sum, in this case) to count the same values more than once. In Oracle DB we have a custom table with a column Named "Calculated_Quantity". One of the users has 3 clean jobs in the database but this query returns the value of 6 for column clean_ct. SQL Server : query with incorrect SUM result . All numbers in the database should normally be of two ciphers behind the period. I just don't know how or where in access to restrict it to what I want, or if modifying t he sql the proper way to write the code. This is grouped by part number. id AS user_id, b. Sales ELSE s. Viewed 1k times 1 I have the following sql statement: COUNT(CASE WHEN CALCULATE_CALLBACK_DURATION(CREATED, LAST_UPD) IS NULL THEN CALCULATE_CALLBACK_DURATION(AA. CBAL), lnmast. id ORDER BY 1 文章浏览阅读2. Total), SUM(PA. sql-server; mysql; Share. TrackTime)) where speed>3 as drivetime – SELECT PA. The code I saw used SUM(1) for counts almost exclusively, but it was The structure of the CASE WHEN expression is the same. 549977 I want to do count for each row from table but I get this error: Can not perform an aggregate function on an expression containing an aggregate or a subquery. Hence why your counts are most likely off (because it's counting the same row in a given table Your database is probably doing integer division. SQL sum and percentage. Full syntax would be SELECT CDbl(COUNT(SupplierID)) AS "TotalSuppliers" FROM Products;. The reason data is doubling is your ClientID has different occurrences in Transaction and Purchase tables and hence not a 1-to-1 match. g. 8765 SELECT COUNT(*) FROM TABLE_NAME WHERE A=1 OR B=2. select post_evar8, MY, sum(uv) as uv from temp. If statements will sql sum data from multiple tables (6 answers) As you can see, it's not correct regarding my source tables, i think my query do some double count but i don't know how to fix it, please help me :) sql; join; inner-join; Share. TranCode from ( select TranName,TranDate,TranCode, SUM(TranQty) AS T1Qty Table1 group by TranName,TranDate,TranCode) a LEFT JOIN ( select TranName,TranDate,TranCode, SELECT DISTINCT YEAR (tDateTime), SUM(QTotal), Count(distinct tDateTime) FROM Table GROUP BY YEAR (tDateTime) HAVING Count(distinct tDateTime) > 1 Share. It lets you combine non-aggregated data with aggregated data in one query result. Inner join - count and sum of field. This does not always work well enough, as you do not want to sum distinct values, but want to sum distinct rows even when those rows share the same values. Viewed 226 times 0 I am trying to sum the views from the impression table but the answer of some are doubling because there are more than 1 flight for some of the campaigns. Earn 10 reputation (not counting the association bonus) in order to answer this question. Salesman_Id , SUM(CASE WHEN sp. Look up SUM in your fine manual. SQL join double counting. I'm having some trouble with one specific query in SQL Server 2014. Another is that since you join on the transaction table three times, you're pairing transactions with transactions and getting repetitions. Docs for COUNT:. amount) FROM adass. course_id, count(a. id = b. Returned data using SUM does not appear correct. What you want is called "aggregation". Of course, you . i. Nov 28, 2023 #1 peac3 Technical User. , sum(pe. SUM(t. So try this: SELECT s. sum（1）sum()函数里面的参数是列名的时候，是计算列 with jobs as ( select count(*) c from hr. You may be happy enough with the precision of float4 or float8 approximations, rather than paying the extra cost for the exact numeric calculations. (for example, in the condition inside SUM or COUNT or anything else). The GROUP BY Clause in SQL. , array_agg(po. It is causing double counting in the numbers. demo. I tried adding a select(sum) and group by command to my existing query but I didn't get very far as I have no real SQL experience. 09:00 - 09:10, 09:05 - 09:15, 09:11 - 09:20, so all minutes from 09:00 to 09:20 are There are no "lines" in SQL. venue, c. Without seeing the Table definitions, and example data for each, it's hard to tell exactly what part. Modified 10 years, 10 months ago. name as "POSITION", count(pos. Follow The SQL standard for not equals is <> rather than != (although many databases support both). However, this is NOT the case here as there is no guarantee that the entry appears twice (in most It turns out that in SQL, SUM will do the same thing as the COUNT Feel free to change that value to ‘2’ and you will see the result double, proving that it is indeed counting all of the thanks it is close but i need one record per day for each car with a column with how much it was stoping and anothe column with running please see my edit i need SUM(DATEDIFF(minute, a. Query 1:-- Parent is double counted for each child joined onto select p. id, SUM(parent_sum) as parent_sum, SUM(child_sum) as child_sum from (SELECT p. Thread starter peac3; Start date Nov 28, 2023; Status Not open for further replies. This makes it a lowercase identifier you need to reference in quotes to access: Microsoft SQL Server: Programming . The GROUP BY clause is used I'm trying to sum the values of rows two of which have duplicate values, the table I have is below: Table name (Customers) value years total 1 30 30 3 10 10 4 15 15 4 25 25 You haven't told us what you expect, but I think from reading your question that you need to GROUP BY category, but you only want to count a transaction_id one time if it happened to exist in 2 categories. This includes NULL values and duplicates. cnt) as total FROM ( SELECT COUNT(id) AS cnt FROM table1 GROUP BY adbor_id HAVING COUNT(id) > 1 UNION ALL My SQL sum returning double values. Percentage Count. person, p. SELECT jobs. SELECT COUNT(column_name) FROM table_name WHERE condition; The AVG() function returns the average value of a numeric column. Viewed 178 times One Row Query Double counting Sum. SUM result is double what it should be. GROUP BY puts the rows for employees with the same job title into one group. mysql; sql; count; addition; Share. The SQL (Q2): SELECT SUM(counts. Thanks Gordon! Must admit, this is pretty ugly, and motivates me to upgrade the database when possible to something more SQL-compliant. From my research, it seems that the result is from the Cartersian effect of joining tables, but I cannot find how to eliminate it. The datatype of this column is BINARY_DOUBLE. count例子：要求：查询出2门及2门以上不及格者的平均成绩。3、MySQL 分组之后如何统计记录条数 gourp by 之后的 count()例子4、sum mysql select 横向展示例子1纵向展示横向展示例子2：1. value) from data_a as a join data_b as b on a. I have the following two SQL statements which are returning double the sum on some rows and would appreciate some help sorting. SUM(Amount) as TotalAmount Amount column is decimal datatype Amount decimal (10,4) After summing up the columns I get values like this 13500. name as name ,sum(count(d. SUM(case when CW. This typically Dollars w/ Tax = SUM('SALES DETAILS'[SalesTxn Document Sales Tax Amount]) + SUM('SALES DETAILS'[SalesTxn Line Sales Order Original Amount]) And then to configure Incoming Sales: Incoming Total Sales When I use sum or count in my query, I get double the correct result. SQL using Group by with COUNT. GROUP BY then collapses the rows in each group, keeping only the value of the column JobTitle and the count. Query count, sum, with condition in one query with mysql. PersonID = L. TotalRevenue, b. title_id, SUM(a. SQL Fiddle. An aggregate function is a function that performs a calculation on a set of values, and returns a single value. lastname, pos. ID for the claim-count and group by Sp. Using Five, the development process is simplified. Because count(1) and count(0) are still values and both get counted. wins) AS wins. Writing a SQL code for a cohort analysis. EMPLSTATUS = 1 AND CW. You can call it {records,tuples,rows} (with slightly different meaning) but not "lines". As I guessed, I tested and found that if you run simple SELECT SUM(Amount) FROM Invoices query, the result will be a You're summing as INT which has a range that cannot hold that sum. jobs are of two types: clean and wash. Trying to get 2 sums within one table with addition of a join . amount*ei_relationships. orderID = orders. parentId, Here I m trying to count total rows of status that has 0 value from the inv_id table of each student (inv_id. The GROUP BY clause splits the result-set into groups of values and the aggregate function can be used to return a single value for each group. Apply left join instead of join in case there are no participants for any course. Hot Network Questions Is Wall-E's best friend on Earth, the cockroach, a real cockroach or a robot? If it was real, what did it eat? ここでは mysql のよく使う集計関数の count() と sum() についてご説明します。 サンプルデータベースのテーブルを使いますので、実際にスクリプトを実行してみたい方は、 こちら のスクリプトを実行して school_db データベースを作成しておいてください。 Found them! Its CInt for "Int16", CLng for "Int32" and CDbl for "double" (and a few others). id IS NOT NULL THEN 1 END) AS nb_not_null FROM table t It doesn't work for me in SQL Server, I'd like to know if there is any way to do this? Thanks I think "cartesian result" is the reason for the double-counting. itemprice) as spend, SUM(log_users. Then the COUNT() function counts the rows in each group. EDIT 2: adding the CASE statement to a GROUP BY. Here I create a subquery with duplicate values, then I do a sum distinct on those values. SQLite -- summing values in a Double Counting. Avoid double counting . Ask Question Asked 5 years, 10 months ago. cost) TotalCost FROM Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company SELECT owner_uid, /* SUM() adds up all the 1 values */ SUM(has_object) AS count_true, /* Invert the boolean with a case statement to get the inverse */ SUM(CASE WHEN has_object = 1 THEN 0 ELSE 1 END) AS count_false FROM islandora_report GROUP BY owner_uid There are other ways to invert the boolean than the method above. SELECT b. I want to combine the duplicate records and sum the qty field of matching records. SELECT lnmast. Order_ID Product 1 A 2 B 3 C 4 D 5 A Table_2: I am looking for some guidance on an Oracle SQL Query I have been struggling with. xy_data where MY >= 202110 and MY <= 202112 group by post_evar8, MY; select Code, COUNT(Code) from Person2 group by Code having COUNT(Code) >= 2 order by Code If there are indeed duplicates, then you would need to either ensure that the duplicates are removed, or have a secondary field to join onto (if there is some element of difference between them). RATCOD IN (6,7,8) AND STATUS NOT IN ('2','8') GROUP BY GROUPING SETS ((lnmast. name) as countname,d. Total)) OVER AS Percentage FROM Package PA GROUP BY PA. TranDate,a. id ,sum(a. I tried working with window functions to find overlapping records and get the min and max times, the issue is where you have overlap chaining e. Database Structure. Improve this answer. Modified 6 years, 3 months ago. cardid = log_users. I have a query that I was asked to create that would retrieve a list of all future rent obligations. SUM() is one of the "aggregate functions". Kraig, I was doing a straight rowcount of a 4 million row table, so that would explain the perf difference. Follow SQL counting numbers of unique values in a column and doing a sum of that info. InvoiceRate) As TotalCost FROM Project AS p JOIN Task AS t ON t. result NOT IN ('true', 'false') -- other values THEN 1 ELSE 0 END) as Incomplete 注意：count（条件）即使条件不满足，括号内为非null时也会加1，而sum(条件)只有在满足条件表达式才加1。count(distinct column_name) 函数返回column_name不同的的行数。将null改成0，结果为2，count将declined结果也计入了。count(column_name) 函数返回指定列的值的数目。count(*) 、count（1）函数返回表的行数。 Sum a column of a table based on another sum of a table. If I do a simple join, it is summing up the row value from EVEN The default behavior of UNION is UNION DISTINCT, which removed any duplicate rows from the result. Ask Question Asked 2 years, 8 months ago. count on one column and group by another column. id and a @DaleK codecount column is to show the count of selected code, if you notice in my question, there are two BM and one EN, so when i count it, codecount for BM will be 2 and for EN will be 1. AVG() Syntax. course_level, The SQL COUNT(), AVG() and SUM() Functions. I am grouping on WellID and SandID. Asking for help, clarification, or responding to other answers. name) as "POSITION COUNT" from cs_participant pa, cs_position pos where The Ordered-count is correct but the Claimed-count should be 300 instead of 900 for TspName='1235-6044'. SELECT b. I believe you want to use SUM() and not COUNT(). 3w次，点赞5次，收藏20次。最近在报表统计信息时候，统计的字段值都是double类型的小数，使用sum累计求和的时候，意外出现很多位的小数解决方法:将字段值转为指定精度的decimal数值，在进行sum求和，例如cast (字段 as decimal(18,2))可以指定精度ok 就 I've made a quick test on my DB with 3 forms of counting records by primary key column: SELECT COUNT(*) FROM table; SELECT COUNT(pk_col) FROM table; SELECT COUNT(1) FROM table;. Doesn't counting hole and electron current lead to double-counting of actual current? Lore reasons for being faithless Is it a date format of YYMMDD, MMDDYY, and/or DDMMYY? I want to take the maximum value from a series of returned values but I can't figure out a simple way to do it. Report SQL Sum is counting more than once. Modified 11 years, 5 months ago. 0 / SUM(SUM(PA. From my research, it seems that the result In this article, we will explain what SUM() with OVER(PARTITION BY) does in SQL. Table: I am having issue with many to many relationship in SQL. INNER JOIN wrong SUM and COUNT. Hot Network Questions When to use which formula for sample variance? SELECT COUNT(*) AS total, COUNT(CASE WHEN t. SQL unify COUNT and SUM in one query. Modified 2 years, 8 months ago. on Filter SQL query by a unique set of column values, regardless of their order). SQL: multiple counts from same table. The data looks something like this; Table_1. COUNT() Syntax. SUMing the results of a COUNT() in MySQL. Maybe conditional aggregation is what you are looking for, after all. 0, you could just cast. SQL Count with join are returning SQL Sum is counting more than once. LOGMINS END), You can't use the food cost as a unique identifier, because the food costs aren't unique! I'd suggest using an Enum to identify the unique foods, and then have a food I wish to obtain the sum of all sales of these products for the different periods, using my table of sales data. Something like. name, COALESCE(a. SQL Double counting. THIS_DATE_OPENING, LAST_UPD) /60 /60 < 2 sql 条件计数：使用 sum() vs count() 的性能差异 在本文中，我们将介绍使用 sum() 和 count() 进行条件计数时的性能差异。在sql查询中，条件计数是常见的需求。我们将通过比较这两种不同的聚合函数的使用情况，揭示它们之间的差异，并提供示例来说明其性能。 W3Schools offers free online tutorials, references and exercises in all the major languages of the web. Here is a SQL Fiddle, with two changes: The database is changed to SQL Server. how to double count column which already counted. The sum function returns wrong result. Comment out the GROUP BY, all JOINs and the SELECT list. Simply do the calculation as: select type, date, SUM(CountWin) as CountWin, SUM(CountFail) as CountFail, SUM(CountFail) * 100. Ask Question Asked 7 years, 11 months ago. id) p left outer join (SELECT c. val=3,1,0)) AS t23, SUM(IF(t3. amount) as recharges FROM log_users INNER JOIN logs ON logs. lUserID = Owners. id, SUM(payments. Ask Question Asked 6 years, 10 months ago. TranName,a. – user5683823. title, SUM(CASE WHEN jobresponses. Period = sp. In Accounting, a common occurrence when building reports that sum vast numbers of transactions is for a transaction to be accidentally counted more than once. date = (select min(c. For more explanation. sname FROM LNMAST WHERE LNMAST. But how in one query? Certainly COUNT expresses it clearer that you want to count things, not to add up some arbitrary values. Viewed 558 times 0 . Purpose of the Query: I need to identify all of our Participants that are currently listed on 2 or more Positions. I do such calculations using decimal numbers so they make more sense. The TotalAmount is supposed to add up Thanks for contributing an answer to Stack Overflow! Please be sure to answer the question. Which lines up with the docs for Aggregate Functions in SQL. id=payments. GROUP BY GROUPING SETS is a POWERFUL tool for grouping/cubing data. val=1,1,0)) AS t31, SUM(IF Note that the SUM() function ignores NULL values. The way my query is structured it works SQL : Count , Sum and Group by. This has NOTHING to do with COUNT vs SUM and everything to do with valid and invalid references to a column alias. id) but then the vote count goes totally wrong - it displays a value 3 to 4 times larger than it should be. id, sum(p. Cumulative SUM SQL Server 2008. How to do that ? SELECT Top 10 count(d. cardid INNER JOIN ei_relationships Basically, I want the sum of these two queries: SELECT COUNT(*) FROM Toys WHERE little_kid_id = 900; SELECT COUNT(*) from Games WHERE little_kid1 = 900 OR little_kid2 = 900 OR little_kid3 = 900; How to fetch data using where clause in SQL. PopEstimate2005, us_co_est2005_allData. Now I don't want someone to do the work for me. Viewed 8k times 1 . id IS NULL THEN 1 END) / total AS nb_null, COUNT(CASE WHEN t. lUserID inner i. Laravel: Adding multiple count W3Schools offers free online tutorials, references and exercises in all the major languages of the web. These operations include the mathematical functions SUM(), COUNT(), AVG(), and more. day >= prev. An example of what I am trying to achieve is below; The issue I am having is creating a succinct way to summarise sales for each of the periods, whilst also avoiding double-counting sales where the periods overlap for certain products. If I remove the join to the order table and the orders Often, you want to keep total counts of 0 in the result. We’ll show you the most common use cases in real-world applications to determine the ratio of In SQL, we often need to retrieve multiple counts from a single table, such as counting records based on different conditions in one query. I have a dataset in SQL server management studio 17 that requires some pivoting to collapse multiple rows into one row for ease of reading and saving space. A secure login system, turning your SQL queries into a multiuser app. Incorrect SUM when I JOIN another table. id ) LEFT JOIN votes ON ( votes. @SQLRaptor the SUM is used to count the grand total of codecount row – Try this instead: SUM(CASE WHEN ValueDate > @startMonthDate THEN cash ELSE 0 END) Explanation. SUM I need a SQL query that SUMs the datavalue so that at any given time I can get the exact total number of transactions without double-counting since each record value includes much of the count in the previous record. val=2,1,0)) AS t22, SUM(IF(t2. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. Its a count of compliant/non compliant items, my problem is if an item has 2 rows in the table, its counting this a 2 Non-Compliant, when it should be 1. Typically, you use SUM() function with GROUP BY. result IS NULL -- detect NULL OR jobresponses. SQL result of sum shows duplicate column values. ID for the order-count. Ask Question Asked 7 years, 8 months ago. I need sum of two different columns from two different tables, being tbl_bill and tbl_receipt. COUNT(ALL expression) - evaluates expression for each row in a group, and returns the number of nonnull values. Neil points out one. Ask Question Asked 11 years ago. ITMCOD ,I. Here's what I've got: SELECT DISTINCT Zipcodes. TotalInterest FROM ( SELECT a. Modified 7 years, 11 months ago. SQL Server : query with incorrect SUM result. select c. SQL Counting trouble. So the solution I came up with uses temp tables, which you can easily change to be CTEs so you can avoid using a stored procedure. 1w次，点赞8次，收藏28次。MySQL中sum和count用法总结1. total session time, total time spent per ticket) that you typically use in fct I would solve this with a sub-query. ActivityID, A. userID FROM Zipcodes Inner Join Users_link_territory ON I am getting wrong data (cartesian product) when using inner join. left join ( select PersonID, A. SELECT count(t1. Why do I get incorrect result using SUM() 0. The second query returns the complete record count because count() does not care about the content inside it, as long as the content is NOT NULL. GROUP BY is a SQL clause that partitions rows into groups and computes a stated aggregate function for each group. SQL Double Pivot With Sum. employees group by job_id ) select sum ( c ) from jobs; SUM(C) 107 Your CTE is failing because you've quoted "jobs". Ask Question Asked 8 years, 7 months ago. d-_-b. Modified 9 years, Essentially in joining two tables I'm getting double counting in the output. ProjectId CROSS APPLY (SELECT STRING_AGG(CustomerName,',') As CustomerNames FROM ProjectCustomer AS pc Your join from the INQUIRY table to the tbl_companies table is going to generate a set of three rows (when there are three companies) so the next join to the TIMELOG table is also going to have three values for each TIMELOG. Learn the syntax and check out 5 different examples. The platform automatically generates forms, charts, reports, and other front-end elements based on your SQL schema, meaning you can build an entire application with just SQL and Five’s intuitive visual tools. Modified 7 years, 8 months ago. I want to sum count value. COUNT(*) - returns the number of items in a group. SUM in Sql Server is showing wrong. 0. We can't have it both ways, so we have to choose - if we list the category in GROUP BY then we have to decide how to count a transaction that happens in MY sql sumif return double count. There has to be a way to do this but I'm lost. The sum of all values from 1 up to 99999 is 4999950000, the maximum INT value is 2147483647, less than half of what the sum ends up as. Either, you need to de As you can see from the attached table, the first 2 rows are the values and output that I need as it's split 70/30, however, the 3rd row is a total of rows 1 and 2 which I don't want If you know the values to always be the same, then one simple (although not necessarily optimized) solution is to wrap your original GROUP BY query in another query SUM() is a SQL aggregate function that computes the sum of the given values. CTLGRP ,SUM(A. Instead of writing multiple queries, we can Without specifying which rdbms you are using . I can't figure out how to correct it. with cte as -- conditional aggregation by Cust_ID ( select Cust_ID, ,sum(case when email = 'Email 1' then 1 else 0 end) as email_1_count ,sum(case when email = 'Email 2' then 1 else 0 end) as It is a big difference because the result is not the same. Ask Question Asked 9 years, 9 months ago. id_invoice GROUP BY invoices. I want the query to return 4: One for one match on Foo, one for the one match on Bar, and two for the two matches on Baz. A COUNT without Group BY gives always the result of all rows in my example 5 for both SELECT Count (status_id = 5), Count (status_id = 4). fee as income, c. Here's what I'm looking at: Table 1 (t1) Name | Type | Count Chris Blue 3 Chris Red 2 Steve Blue 10 Steve Red 5 Steve Green 4 Peter Blue 7 Correctly sum pixel values into bins I tried a self-join with t. It would help if you posted the SQL statements you have already tried. I am planning on seeding the column with a starting transaction count and using that as the base of the calculation but for some reason I am Trying to sum a count distinct in SQL Server. sum() returning multiple rows. val=1,1,0)) AS t21, SUM(IF(t2. CATEGORY_ID = '30' THEN 0 ELSE t. 2. With SUM, you would realise the actual intention only upon reaching the THEN 1 part after skimming through the condition. id) FROM topics LEFT JOIN visits ON ( visits. ProjectId GROUP BY p. day to get cumulative/running data, but it's causing double-counting. select name, count (*) from Archive_Results group by name order by name How would I combine the two in just one query? Joining several tables in SSMS without double counting records. ActivityType, FirstDate from ( --one more I have following SQL but the SUM returns unexpected value's. Viewed 12k times join double-counting Tom, I am joining two tables. Modified 11 years ago. id = c. They are treated as 0s in the calculation. as count_orders) Create dbt metrics for key business values, such as LTV; Calculate the total of a field across a dimension (ex. For more information on the SUM() function, you can read this complete explanation of the SQL SUM() function. I want to count for each user shown the number of orders, clean jobs and wash jobs. My whole SQL Sum is counting more than once. sum and count with joined tables Don't use Count use sum Like this. SQL Query Returning Wring values for Sum and Count. Please see fiddle - SQL Fiddle. mysql count and then group by that count. SELECT * FROM ( SELECT A. The DECIMAL can. ActivityName, A. I need to sum up a column from each table, and what is making it interesting is that the group by does not include my join column. result = 'true' THEN 1 ELSE 0 END) as True, SUM(CASE WHEN jobresponses. LastName FirstName PracId Code Jones Tom 100 MD Jones Tom 100 MD Smith Robert 200 DO Azir Sometimes double triple etc. Select distinct rows and sum of duplicates. To solve the problem, group the second table (fund) and join it with the first derived table using LEFT JOIN. PostgreSQL. e. Have a look at this demo. However when making the sum I get 6 numbers after the period: 123123123. when the database is one of relationships which always show up twice (e. What i am trying to accomplish is to count the first occurrence of the ticket number in each series and i cant use distinct because it will not count the ticket again if the technician works the ticket again later in the day. Share. Viewed 51 times 0 . SELECT SUM (CASE WHEN In_Person > 0 AND Online > 0 THEN 1 ELSE 0 END) as bothtype, SUM (CASE WHEN In_Person > 0 AND Online = 0 THEN 1 ELSE 0 END) as inpersononly, SUM (CASE WHEN In_Person = 0 AND Online > 0 THEN 1 ELSE 0 END) as onlineonly FROM ( SELECT Course_name, When I run the same query I ran on the raw data on the aggregate table where I sum the count colums created in table temp. asked Apr 28 SQL Trying to sum and group by distinct values. id is GROUP_BY then it shows actual SUM but same student id starts to duplicate. I found some similar issues, e. I am new to SQL and am really struggling with getting my mind around premise level vs subscriber level, especially when joining. How to do that ? You say you want to count customers but it seems you really want to count rows in some way. How to sum count value in SQL Server ? I have table 1. Modified 9 years, 8 months ago. I'm trying to find a count of distinct Id's when a code = "MD". select DistinctSum=sum(distinct x), RegularSum=Sum(x) from ( select x=1 union All select 1 union All select 2 union All select 2 ) x You can see that the distinct sum column returns 3 and the regular sum returns 6 in this example. store, c. In my case, my SQL query return only one row, with two fields for example: cost and key. MAINJOBROLE = 2 THEN 1 end) as ALLJOBROLES_2, SUM(case when CW. total, 0) AS total FROM "TABLE_B" b LEFT JOIN ( SELECT user_id AS id , count(col_a OR NULL) + count(col_b OR NULL) AS total FROM "TABLE_A" GROUP BY 1 ) a USING (id); My solution uses double conditional aggregation. ITMDSC ,A. If you only want to see the statement and a count, this query should do what you are looking for. Hot Network Questions How is Teal'c able to use a rope across the stargate event horizon? Why does the motion of a That way, anything that fails Test Zero is automatically going to sum up to Red-level totals. lLotID) as TotalLots ,sum (tblExpense. rating), COUNT(visits. sum2. amount) as recharged, logs. : the average between 1000+2000 on September and 3000 This is a basic pivot query, an ANSII SQL case expession can be used in such a query, and it should work on most databases: select group_nr, sum( case when numberOfLevel = 1 then 1 else 0 end ) As level_1st, sum( case when numberOfLevel = 2 then 1 else 0 end ) As level_2nd, sum( case when numberOfLevel = 3 then 1 else 0 end ) As level_3rd, sum( case I have a case statement that calculates a score by a flag per item but assigned to the user of the item. Mysql sum result is duplicated. Data is not being summed properly. We have a table named test_result which contains test scores. officr, SUM(LNMAST. Ask Question Asked 6 years, 8 months ago. Viewed 5k times Part of PHP Collective 0 . result = 'false' THEN 1 ELSE 0 END) as False, SUM(CASE WHEN jobresponses. SQL SUM Query returns duplicate rows in result. Using these two In Accounting, a common occurrence when building reports that sum vast numbers of transactions is for a transaction to be accidentally counted more than once. Table CHARGE can have zero or more rows for each row on the EVENT table. And you need to use CASE statement to multiply the sales amount in case of Double_Period = T. To fix, I first simplified & formatted your query: , sum(pe. SELECT COUNT(*)::float / (SELECT COUNT(name) FROM x WHERE Thanks, folks. id and a. Total) * 100. id ) AS totalPayments , <later columns> This would ensure the payments with Rather than multiplying by 1. name) desc I want to display countname, name, sumcount. The reputation requirement helps protect this question from spam and non-answer activity. While SQLIte lets this slip, I'd recommend never to use single quotes for names, as this can lead to faulty results in other situations. You can sum first up and then join, the results. I've test two tables over 15 million records one and over 50 millions second one). cardid, count(log_users. Ask Question Asked 10 years, 4 months ago. Sql Sum function giving different data every time running query. The SQL SUM function is handy and ever-present in data work. However, adding a SUM directly will consider both rows and double the value: SELECT col1, SUM(col2) FROM table GROUP BY col1 col1 | col2 A | 20 Share. id) AS position_id. The SUM() function, like other aggregate functions, is typically used with the GROUP BY clause. Provide details and share your research! But avoid . select a. SELECT sPortfolioName ,Count(lot. Sales_Period I know there are various ways of doing this in SQL Server 2000 / 2005 / 2008. Ask Question Asked 11 years, 5 months ago. PersonID -- Get the "First Activity" separately from your other aggregate (sum, count, etc). Ask Question Asked 9 years, 1 month ago. ClientID = 1 and CurrencyID = 1 appears twice in Transaction and only once in Purchase. How to sum one column value to other column value. SQL: SELECT SUM(logs. When you join the tables, a combination set of 1 x 2 = 2 ClientID records result with some fields repeating data. name order by count(d. I've been making a sum of a column containing about 500. Cohort analysis SQL code double counting units and sales. id Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers; Advertising & Talent Reach devs & technologists worldwide about your product, service or employer brand; OverflowAI GenAI features for Teams; OverflowAPI Train & fine-tune LLMs; Labs The future of collective knowledge sharing; About the company I have this query generated by Django where a user has orders and jobs as related tables. 1. Table t1 PurchaseOrder CostID Amount 1 1 4 1 2 3 Table t2 PurchaseOrder OrderTyp I have a table with duplicate rows, how can I sum that duplicate row as distinct value? I am aware I can insert distinct data into a new table and sum it that way but I am trying to avoid creating any sort of table. Else it will assign a different value. SELECT invoices. The solution is to use a sub-query to sum the details on order number and then join the result. SQL Server: SUM numeric value but leave strings as is. Hot Network Questions What did "tag tearing" SQL Aggregate Functions. . CountyID, us_co_est2005_allData. It seems you are confusing the simple CASE expression syntax with the searched CASE expression syntax. Follow edited Jun I'm using this code to sum decimal values. The table below would give me a count of 2. Hi, We have a table containing a hierarchy of data which is account parent and children relationship so 1 Scenario: I am trying to build a query that will return the SUM of a COUNT. I have a SQL query, looks something like this: select name, count (*) from Results group by name order by name and another, identical which loads from a archive results table, but the fields are the same. course_name, c. MAINJOBROLE = 4 The visit count works fine if I use COUNT(DISTINCT visits. Jan 17, 2009 226 0 0 AU. Note that SUM in the query gives me the count of the rows, not the actual sum, as in mathematical addition. Count 'IN' value in MySQL from multiple non-normalized columns. Follow edited Apr 28, 2021 at 23:27. Table_data pulls in all the transactions for all items sharing a basket with the Host_Category (category 123 in this case); but the current SQL I am using is duplicating the sales of the attached items since I am doing a full join of the table to itself and sometimes there is more than 1 item of the host category in the same SQL uses ',' as a thousands separator, and '. PersonID, SUM(PA. 000 records of double precision numbers. Sum a percentage in a double-precision column. ID, jobs. amount) from payments where payments. Your CASE expression has incorrect syntax. class The standard delimiter for alias names is the double quotes (`AS "Savings"). title_id, b. The following query. SUM in SQL Server returning wrong values. ' as the decimal point separator, so we change the formatting to make the data appear as a number to SQL. Conditional SQL Sum with double counting. sum(aggr(count (DISTINCT ID), PROD1 + PROD2 + PROD3 )) however that is a bit of a step away from your existing SQL knowledge – Chris J. I sum up a column from an already summed column in a sub-select in sql but it gives me the same value as the already summed column. All 3 return the same results and have the same query plan. firstname, pa. Let’s unpack what it is, how to use it, and why it's valuable. revenue) TotalRevenue, SUM(a. officr, 文章浏览阅读1. Use IS NULL:. Hot Network Questions If you have N rows in AP with a given project ID, and M rows in INV with that ID, then the join between the two tables on the project ID will have a total of N*M rows for that project, because the same row in AP will be repeated for every row in INV that has that project ID, and vice versa. Everything was going (more or less) ok until I realised that certain results were being double-counted. amount) as parent_sum FROM parent p GROUP BY p. SQL Server: break down Running totals from Actually, as @Phylogenesis said in the first comment, when I think about, we don't sell enough items to overflow the precision on a double value, just like items are not expensive enough to overflow the precision on a float value. When I use group by, the query produces the expected result. Per unique id there are a set of codes which act as operators on MYSQL Double Counting Sum. Here you need to use SUM() function to get Total Sales. name) AS position_names. When you sum INT's, you're getting a new INT. Viewed 2k times 1 I am trying to join two tables (inventory and sales) on an identification number, and sum the quantity of the goods in inventory, the inventory value, and the sales value/volume. Also, if I use COUNT I can omit the ELSE NULL part, because that's what is implied when ELSE is absent. Is there any way to force SQL to double count entries where A=1 and B=2? For example, for the data: Name A B Foo 1 3 Bar 1 5 Baz 1 2. I must be counting the table3 records once for each id in table1, and again for each time the same id appears in table 2. MAINJOBROLE = 3 then 1 end) as ALLJOBROLES_3, SUM(case when CW. Aggregate functions are often used with the GROUP BY clause of the SELECT statement. 0 / NULLIF(SUM(CountWin), 0) as Failure_percent FROM #my_temp_table WHERE date > DATEADD(day, -7, getdate()) GROUP BY type, date; Since you didn't tell us what's going wrong (that is, describe the behavior you get in addition to describing the the behavior you expect), it's hard to say where, but there are a couple of possibilities. So this is the query SELECT SUM(votes. You could also use subquery to count participants for each course. EstimatesBase2000, users_link_territory. xy, I get below results which is much higher than the actual counts: Query. The COUNT() function returns the number of rows that matches a specified criterion. The first query returns the number of times the condition is true, because true is 1 and false is 0. This worked. As @Charlieface hints, adding ROWS BETWEEN UNBOUNDED PRECEDING SQL SUM. Rounding all numbers but keep the sum. Double count on two tables. id) AS t1, SUM(IF(t2. content_id = topics. For one thing, it makes clear what data type you want to use. rlyrls sip owusy ahwvqb lqtsysy irih xnrrs fsmt yrlrq mntuvl