Hackerrank occupations. My solution for MSSQL.

Hackerrank occupations I translated your solution to something that works in MS SQL. Leaderboard. WITH ctc AS (SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS row_num FROM occupations ) SELECT MAX(CASE WHEN occupation ='Doctor' THEN name END)AS Doctor, MAX(CASE WHEN occupation ='Professor' THEN name END)AS Professor, MAX(CASE WHEN occupation ='Singer' THEN Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Occupation, a. Return to all comments → Really good stuff. Works with Mysql: # with base_tab as ( select case when occupation ='Doctor' then name else null end as doctor, case when occupation='Professor' then name else null end as professor, case when occupation='Singer' then Name else null end as singer, case when Occupation='Actor' then Name else null end as actor from OCCUPATIONS), doctor_tab as ( select row_number() In this part of the query, we use conditional aggregation to pivot the data. Please signup or login in order to view this challenge. SELECT DocTable. The output column headers should be Doctor, Professor, Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH RankedOccupations AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name ELSE NULL END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name ELSE NULL END) AS Professor, MAX(CASE Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Occupations. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Name, (SELECT COUNT(*) FROM Occupations AS b WHERE a. The output column headers should be Doctor, Profe Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH CTE AS ( SELECT Occupation, Name, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupations. These recursive functions you constructed {@r1:=@r1+1} is basically the same as creating a rank column partitioned by Occupation:with cte as ( select RANK() OVER (PARTITION BY Occupation ORDER BY Name) as Rank, case when Occupation='Doctor' then Name else null end as Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. So add Hi All, could anyone support me to know why the below query is wrong? SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE 'NULL' END) Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE 'NULL' END) Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE 'NULL' END) Singer, MAX(CASE WHEN occupation Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The output column headers should be Doctor , Professor , Singer Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. WITH ranked AS ( SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS rn FROM OCCUPATIONS ), pivoted AS ( SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Except for it's giving Occupation name as the 1st column, I don't understand why this is not working, can some explain please. Here I see the answer is quite tough for me to solve. MY SQL Solution. Yes, little bit harder for me too :-) This query creates the ranking value, smaller values are in alphabetical order. My solution for MSSQL. SELECT rank, MAX(CASE WHEN Occupation = 'Doctor' THEN Name ELSE NULL END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name ELSE NULL END) AS Professor, MAX(CASE Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SELECT MAX(CASE WHEN occupation='doctor' THEN NAME ELSE NULL END) AS doctor, MAX(CASE WHEN occupation='professor' THEN NAME ELSE NULL END) AS professor, MAX(CASE WHEN occupation='singer' THEN NAME ELSE NULL END)AS singer, MAX(CASE WHEN occupation='actor' THEN NAME ELSE NULL END)AS actor FROM ( Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Sql Server. Means When it finds actor it increments the value a for doctor it increments the value d for professor it increments the value p for singer it increments the value s then I used group by so that I can combine the all for count parallely means by this I wanna show the first of all the occupation's name together so that it can take a proper table form. Occupation = b. WITH*** temptable*** AS ( SELECT CASE WHEN OCCUPATION = 'Doctor' THEN Name ELSE NULL END Doctor, CASE WHEN OCCUPATION = 'Professor' THEN Name ELSE NULL END Professor, CASE WHEN OCCUPATION = 'Singer' THEN Name ELSE NULL END Singer, CASE WHEN OCCUPATION Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. You are viewing a single comment's thread. HackerRank,SQL,Advanced Select,Occupations,MySQL,DB2,Hive,APDaga,DumpBox,PIVOT,SET,Akshay Daga,CASE WHEN,GROUP BY,ORDER BY,List of Names by profession. @arati1626 @himanshimathpal1 To clarify this, first you need to create row number of each record partitioned by its occupation in the entity This approach is easy to use and understandable. Very easy to understand solution: with doc as ( select Name as Doctor,row_number()over(order by name) as rn from occupations where occupation = 'Doctor' ), prof as ( select Name as Professor,row_number()over(order by name) as rn from occupations where occupation = 'Professor' ), sing as ( select Name as Singer,row_number()over(order by name) as rn from And the 'AS Row_Number' part to give a name to that 3rd column being the partition count To see the full table run this query SELECT *, ROW_NUMBER() OVER(PARTITION BY Occupation ORDER BY Name) AS Row_Numer FROM Occupations; Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. I am using idn to combine the result properly. WITH doctors AS (SELECT name AS doctorName, ROW_NUMBER OVER (PARTITION BY OCCUPATION ORDER BY name) AS rn FROM OCCUPATIONS WHERE occupation = ' Doctor '), professors AS (SELECT name AS professorName, ROW_NUMBER () Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. The output column headers should be Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. it is given Alias for CTE use it can be anything i. Return to all comments → Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Hackerrank SQL challenge: Occupations. The output column headers should be Doctor, Professor, Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Modified 1 month ago. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Return to all comments → The contest creator holds HackerRank harmless from and against any and all claims, losses, damages, costs, awards, settlements, orders, or fines. NAME, SingTable. Ask Question Asked 2 years ago. Create a HackerRank account Be part of a 23 million-strong community of developers. Step 3: Select the columns and order the results Occupations. . e. Return to all comments → WITH RankedOccupations AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Here, we have columns- name, occupation and rank (generated for each occupation using ROW_NUMBER() function) Since 1st it is partitioned by occupation, it gives values sorted in asc order according to occupation and then sorts the names as asc order. I even can understand the answer given in discussion section. SELECT Occupation, MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH RankedOccupations AS ( -- Assign a row number to each name based on their occupation and sort them alphabetically SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) -- Pivot the table by occupations SELECT You basicly create an CTE that includes the OCCUPATIONS table plus an added ID column, this is needed for sorting the results correctly, this is the CTE I called KEYED_OCCUPATIONS. sql at master · raleighlittles/HackerRank-SQL Occupations. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. I'm new to SQL and struggled to find the solution for about 2 days in my spare time. Problem. SELECT a. Return to all comments → For those who are struggling for a simple solution. ORDER BY Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. with doctor as ( select name as name, row_number() over (order by name) as row_num from occupations where occupation = 'doctor' order by name asc ), prof as( select Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SET @max_rows:= (SELECT COUNT(DISTINCT Occupation) FROM OCCUPATIONS);. Annotated solutions to HackerRank's SQL domain questions. We create columns for each occupation (Doctor, Professor, Singer, Actor), and for each row number (rn), we pick the name that belongs to the respective occupation and place it in the corresponding column. Learn more here. SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, MAX(CASE WHEN Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Discussions. Name) AS rank FROM Occupations AS a Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Submissions. /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. The below SQL query works fine on SQL Server. Viewed 20k times 2 . - raleighlittles/HackerRank-SQL Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH add_id AS( SELECT *, ROW_NUMBER() OVER(PARTITION BY occupation ORDER BY name) as id FROM occupations), doctor AS( SELECT id, name FROM add_id WHERE occupation = 'doctor' ), professor AS( SELECT id, name FROM add_id WHERE occupation = 'professor' ), singer AS( SELECT id, name FROM add_id WHERE occupation = Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Doctor and other occupations columns contain only a single value for each ranks, so you can reduce null value by MAX or MIN aggregate function with group by rank value. - HackerRank-SQL/Occupations. SELECT MAX(CASE WHEN Occupation='Doctor' THEN Name ELSE NULL END) AS 'Doctor',MAX(CASE WHEN Occupation='Professor' THEN Name ELSE NULL END) AS 'Professor',MAX(CASE WHEN Occupation='Singer' THEN Name ELSE NULL END) AS 'Singer',MAX(CASE WHEN Occupation='Actor' THEN Name ELSE NULL END) AS 'Actor' In my solution I have solved it but my solution is not flexible but It is very easy to understand let me explain you here in the question I have constructed 4 new tables each tables consisting of names of specific occupation and rno which contains the serial number of record. This ID column is special though, it gets recalculated for every group of Occupation values, this makes sure that while the SELECT clause is running, it will Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Most ones can solve the problem but i can't. select [Doctor] as Doctor, [Professor] as Professor, [Singer] as Singer, [Actor] as Actor from (select name, occupation, ROW_NUMBER() OVER ( PARTITION BY Occupation ORDER BY Name) as row from occupations) occup pivot (min(name) for occupation in ([Doctor], [Professor] ,[Singer],[Actor])) as pivottable; SELECT * FROM OCCUPATIONS ORDER BY NAME; Output: Aamina Doctor Ashley Professor Belvet Professor Britney Professor Christeen Singer Eve Actor Jane Singer Jennifer Actor Jenny Singer Julia Doctor Ketty Actor Kristeen Singer Maria Professor Meera Professor Naomi Professor Priya Doctor Priyanka Professor Samantha Actor. NAME, ActTable. Occupation AND a. Return to all comments → Occupations. WITH t1 AS (SELECT name AS doctor, ROW_NUMBER OVER (ORDER BY name) AS row_num FROM occupations WHERE occupation = ' Doctor '), t2 AS (SELECT name AS professor, ROW_NUMBER OVER (ORDER BY name) AS row_num FROM occupations WHERE occupation = ' Professor '), t3 AS (SELECT name AS singer, ROW_NUMBER OVER Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Step2 : Recombine rows : use group by (need at least one same property ) Because we want the result looks like this row1: the first in Doctor; the first in Professor; the first in Singer; the first in**Actor**. NAME, ProfTable. The output should consist of four columns ( Doctor , Professor , Singer , and Actor After searching and learning from internet, the correct answer for this challenge by using MYSQL: SELECT ROW_NUMBER() OVER(PARTITION BY Occupation. Code directly from our platform, which supports over 30 languages. row2: the second in Doctor; the secondin Professor; the second in Singer; the second in Actor. Then same property I need in result is rollnumber . Name > b. NAME FROM (SELECT OCCUPATION, [NAME], ROW_NUMBER() OVER(PARTITION BY OCCUPATION ORDER BY [NAME] ASC) AS ID FROM OCCUPATIONS WHERE OCCUPATION = 'Doctor') As DocTable FULL OUTER JOIN Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. In mysql: Occupations. Select MAX(CASE WHEN Occupation = 'Doctor' Then Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' Then Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' Then Name END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' Then Name END) AS Actor FROM ( Select *, ROW_NUMBER() OVER I used a similar query, but my order for the professors is incorrect. kfxzumiox rso abkyl ylikqd hmaci gle exyygp epj opvi cgyph